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Question

A point P lies on the circle x2+y2=169. If Q=(5,12) and R=(12,5), then the angle QPR is

A
π6
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B
π4
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C
π3
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D
π2
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Solution

The correct option is B π4
x2+y2=(13)2
radius =13 center (0,0)
Equation of OQ=y=125x5y12x=0
Equation of OR=y=512x12y+5x=0
Angle between OQ and OR
tanθ=∣ ∣ ∣ ∣1255121+(1)∣ ∣ ∣ ∣=θ=π2QPR=12QOR=π4

891894_574744_ans_9227f3386cec49138442ceff68f852a3.png

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