A point P lies on the line y = 2x in the first quadrant. Another point Q lies on the line y = 3x in the first quadrant. Suppose QP is perpendicular to the line y = 2x and QP = 5. The distance of P from the origin is:

$7 \sqrt{3}$

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$25$

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$35$

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$39$

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Solution

The correct option is C
$35$

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Similar questions

A point $P$ lies on the line $y = 2 x$ in the first quadrant. Another point $Q$ lies on the line $y = 3 x$ in the first quadrant. Suppose $Q P$ is perpendicular to the line $y = 2 x$ and $Q P = 5$ . The distance of $P$ from the origin is:

Q. If P is a point on the line

y = 2 x

in the first quadrant, and the distance from the origin to point P is

5

, find the approximate coordinates of point P.

Q. If the origin lies on a line, which is perpendicular to the line with equation

y = 2 x + 5

at point

S

, find the distance from the origin to point

S

If X = -3 and Y = -4 are two perpendicular lines. Point P (-3, 1) lies on the line X = -3. Find the perpendicular distance(in units) from the point P to the line Y = -4.

Q. State True or False and write the correct statement.
1. In the cartesian plane the horizontal line is called Y-axis.
2. In the cartesian plane the vertical line is called Y-axis.
3. The point which lies both the axes is called origin.
4. The point

(2, - 3)

lies in the third quadrant.
5.

(- 5, - 8)

lies in the fourth quadrant.
6. The point (-x,-y) lies in the first quadrant where

x < 0, y, 0.

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A point P lies on the line y = 2x in the first quadrant. Another point Q lies on the line y = 3x in the first quadrant. Suppose QP is perpendicular to the line y = 2x and QP = 5. The distance of P from the origin is:

The correct option is C 35

The correct option is C
$35$