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Question

A point ρ lies on the axis of a ring of mass M and radius α, at a distance α, from its centre C, A small particle starts from ρ and reaches C under gravitational attraction only.Its speed at C will be


A

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B

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C

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D

Zero

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Solution

The correct option is B


Increase in KE = decrease in PE

12mv2=m(ViVf)

v=2(ViVf)

=2[GM2α+GMα]

= 2GMα(112)


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