A point size body of mass $20 g$ is revolving along a circle of radius $0.5 m$ at a speed $2 m / s$ , its angular momentum is:

0.02 k g m^{2} s^{- 1}

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0.04 k g m^{2} s^{- 1}

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0.2 k g m^{2} s^{- 1}

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0.4 k g m^{2} s^{- 1}

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Solution

The correct option is B $0.02 k g m^{2} s^{- 1}$
$m = 20 g$
$ν = 2 m / s$
$R = 0.5 m$
$L = m ν R$
$= (.020) (2) (0.5)$
$= 0.02 k g m^{2} / s$

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