wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A point source emitting 628 lumen of luminous flux uniformly in all directions is placed at the origin. Calculate the illuminance on a small area placed at (1.0 m,0 0) in such a way that the normal to the area makes an angle of 37 with the X-axis

Open in App
Solution

l=Luminous intensity

=6284π=50 candela

r=1m,θ=37

So, illuminance e=cos θr2

=50×cos 3712

=50×(4/5)1=40 lux


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon