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Question

A point source is placed at a depth h below the surface of water (refractive index =μ).

(a) Show that light escapes through a circular area on the water surface with its centre directly above the point source.

(b) Find the angle subtended by a radius of the area on the source.

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Solution

(a) Let P is a point source placed at a depth h.

Clearly from figure, the light escapes at a fixed distance r at water surface.

That makes a circle whose centre is just above P.

sin θ=1μ

v=sin1 (1μ)


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