A point source is placed at a depth h below the surface of water (refractive index =μ).
(a) Show that light escapes through a circular area on the water surface with its centre directly above the point source.
(b) Find the angle subtended by a radius of the area on the source.
(a) Let P is a point source placed at a depth h.
Clearly from figure, the light escapes at a fixed distance r at water surface.
That makes a circle whose centre is just above P.
⇒sin θ=1μ
⇒v=sin−1 (1μ)