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Question

A point source of light is placed at a depth of h below the surface of water of refractive index μ. A floating opaque disc is placed on the surface of water so that light from the source is not visible from the surface. The minimum diameter of the disc is

A
2h(μ21)1/2
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B
2h(μ21)1/2
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C
h2(μ21)1/2
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D
h(μ21)1/2
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Solution

The correct option is A 2h(μ21)1/2
The figure shows incidence from water at a critical angle θc for the limiting case.
Now, sinθc=1μ
so that tanθc=1(μ21)1/2
From figure, tanθc=rh
where r is the radius of the disc.
Diameter of the disc 2r =2htanθc,d=2h(μ21)1/2
1089595_942417_ans_b7d80c5add4c4605bdc45f85605f8af5.png

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