wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A point traversed half of the distance with a velocity v0. The remaining part of the distance was covered with velocity v1 for half the time and with velocity v2 for the other half of the time. The mean velocity of the point averaged over the whole time of motion

A
v0+v1+v23
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2v0+v1+v23
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
v0+2v1+2v23
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2v0(v1+v2)(2v0+v1+v2)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 2v0(v1+v2)(2v0+v1+v2)
Let 2S be the total distance travelled
For first half of the journey
S=v0×t1 (where t1 is the time taken to complete half of the distance)
For the remaining part of the journey we can say,
v1t+v2t=S

t=sv1+v2
Total time = t1+2t
Mean velocity = Total displacementTotal time
=2S(Sv0)+2(Sv1+v2)

=2(1v0)+(2v1+v2)

=2v0(v1+v2)(2v0+v1+v2)

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Speed and Velocity
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon