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Question

A point traversed half of the distance with a velocity v0. The remaining part of the distance was covered with velocity v1 for one-third of the remaining time and with velocity v2 for the remaining time. The mean velocity of the point averaged over the whole time of motion

A
v0+v1+v23
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B
2v0+v1+v23
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C
3v0(v1+2v2)(2v0+v1+2v2)
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D
2v0(v1+2v2)(3v0+v1+2v2)
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Solution

The correct option is D 2v0(v1+2v2)(3v0+v1+2v2)
Let 2S be the total distance travelled

For first half of the journey
S=v0×t1 (where t1 is the time taken to complete half of the distance)

Let t be the time taken to complete other half of the journey

For the remaining part of the journey we can say,
v1×t3+v2×2t3=S
t=3Sv1+2v2
Total time =t1+t

Mean velocity=Total displacementTotal time
=2S(Sv0)+(3Sv1+2v2)
=2(1v0)+(3v1+2v2)
=2v0(v1+2v2)(3v0+v1+2v2)

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