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Question

A point z moves on the curve |z43i|=2 in an argand plane. The maximum and minimum values of |z| are

A
2,1
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B
6,5
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C
4,3
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D
7,3
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Solution

The correct option is D 7,3
Let w=4+3i.
We can write, |z|=|(zw)+w|. Hence by triangle inequality (|z1+z2||z1|+|z2|), we can write |z||zw|+|w|. It is given in the question that, |zw|=2 and |w|=42+32=5.
Putting the values, we get |z|7.
Using another result of triangle inequality (|z1||z2||z1+z2|), we can write |zw||w||zw+w|.
Hence, we get |z|3. The minimum value is 3 and maximum value is 7.
Hence, (D) is the correct option

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