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Question

A polarizer-analyzer set is adjusted such that the intensity of light coming out of the analyzer is just 10% of the original intensity. Assuming that the polarizer-analyzer set does not absorb any light, the angle by which the analyser need to be rotated further to reduce the output intensity to be zero is

A
45o
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B
71.6o
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C
90o
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D
18.40
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Solution

The correct option is D 18.40
Intensity after polarisation through polaroid=Iocos2ϕSo, 0.1Io=Iocos2ϕcosϕ=0.1cosϕ=0.316
Since, cosϕ<cos45o therefore, ϕ>45o
If the light is passing at 90o from the plane of polaroid, then its intensity will be zero.
Then, θ=90oϕ therefore, θ will be less than 45o. So, the only option matching is option d which is 18.4o

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