Question

A pole $6m$ high costs a shadow $2\sqrt{3}m$ long on the ground then find the sun's elevation..

Answer 1

R.E.F image

Given height of pole =6m

length of shadow =$2\sqrt{3}m$

Let '$\theta$ ' be elevation. of sum then

$tan\theta$ =$\frac{AB}{BC}=\frac{6}{2\sqrt{3}}$

$tan\theta =\sqrt{3}$

$tan\theta =tan\frac{\pi }{3}$

then $\theta =\frac{\pi }{3}$

$\therefore$ Angle of elevation of sum is ${60}^{\circ }.$