A pole has a height of 45 m and casts a shadow of x m. If a flag of 10 m is kept on the pole, the shadow of the arrangement will be 15 m in length. Find the value of x.

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Solution

The two triangles are similar

$\frac{A B}{B C} = \frac{D B}{B E}$

$X = \frac{45 \times 15}{55} = \frac{135}{11}$ =12.27 m

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A pole has a height of 45 m and casts a shadow of x m. If a flag of 10 m is kept on the pole, the shadow of the arrangement will be 15 m in length. Find the value of x.

The two triangles are similar ABBC=DBBE X=45×1555=13511=12.27 m

The two triangles are similar

$\frac{A B}{B C} = \frac{D B}{B E}$

$X = \frac{45 \times 15}{55} = \frac{135}{11}$ =12.27 m