A pole of $6$ metres in height casts a shadow of $3.6$ metres at a certain time of the day. Find the length of the shadow cast by a $4.5$ metres tower at the same time.

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Solution

The length of the pole is in proportion to length of the tower and shadow of the pole is in proportion to shadow of the tower.
Let length of shadow cast by tower = s
Then, $\frac{T o w e r l e n g t h}{P o l e l e n g t h} = \frac{T o w e r S h a d o w}{P o l e S h a d o w}$
$\frac{4.5}{6} = \frac{s}{3.6}$
$s = \frac{4.5 \times 3.6}{6}$
$s = 2.7$ m
Length of shadow casts by tower $= 2.7 m$

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A pole of 6 metres in height casts a shadow of 3.6 metres at a certain time of the day. Find the length of the shadow cast by a 4.5 metres tower at the same time.

The length of the pole is in proportion to length of the tower and shadow of the pole is in proportion to shadow of the tower.Let length of shadow cast by tower = sThen, TowerlengthPolelength=TowerShadowPoleShadow4.56=s3.6s=4.5×3.66s=2.7 mLength of shadow casts by tower =2.7m

A pole of $6$ metres in height casts a shadow of $3.6$ metres at a certain time of the day. Find the length of the shadow cast by a $4.5$ metres tower at the same time.