Question

A pole stands vertically, inside a triangular park $ABC$. If the angle of elevation of the top of the pole from each corner of the park is same, then the foot of the pole is at the:

• A. centriod
• B. circumcentre
• C. incentre
• D. orthocentre

Answer 1

The correct option is B circumcentre

If angle of elevation$\left(p\right)$ is same from all the vertices then the Pole must be at Equal Distance from each of the vertices which will be $=R\left(Circumradius\right)$

as $\tan p=\frac{H}{R}\Rightarrow R=\frac{H}{\tan p}$[which is same from all vertices]

therefore, the pole must be lying on the $Circumcenter$