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Question

A police jeep is chasing a culprit going on a motorbike . The motorbike crosses a turning at a speed of 72 km/hr. The jeep follows it at a speed of 90 km/h, crossing the turning ten seconds later than the bike. Assuming that they travel at constant speeds, how far from the turning will the jeep catch up with the bike?

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Solution

Vp=90 km/h=25 m/s.
Vc=72 km/h=20 m/s.
In 10 sec culprit reaches at point B from A.
Distance converted by culprit S=vt=20×10=200 m.
At time t=10 sec the police jeep is 200 m behind the culprit.
Time =s/v=200/5=40 s. (Relative velocity is considered).
In 40 s the police jeep will move from A to a distance S, where S=vt=25×40=1000 m=1.0 km away.
The jeep will catch up with a bike, 1 km far from the turning .
1551914_1315779_ans_77a641bef1ac477f8c35158714413a55.png

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