A police jeep is chasing with, velocity of 45km/h, a thief in another jeep moving with velocity 153km/h. Police fires a bullet with muzzle velocity of 180m/s. The velocity it will strike the car of the thief is
A
250m/s
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B
150m/s
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C
27m/s
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D
450m/s
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Solution
The correct option is B150m/s Given:
Velocity of police jeep (VP)=45km/h=45×518=22518=12.5m/s
Velocity of thief jeep (VT)=153km/h=153×518=42.5m/s
Muzzle velocity of bullet (Vb)=180m/s
Therefore, Effective speed of the bullet
= speed of bullet + speed of polic jeep
Effective speed of the bullet=180m/s+12.5m/s
Effective speed of the bullet =192.5m/s
Hence,
Velocity of the bullet with respect to thief’s car (VBT) VBT=Effective speed of the bullet−VT=192.5m/s–42.5m/sVBT=150m/s