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Standard XII

Physics

Relative Velocity in 2D

A police jeep...

Question

A police jeep travelling at a speed of $45 km/h$ is chasing a thief's car moving at a speed of $153 km/h$ . If police fire a bullet with a muzzle velocity of $180 m/s$ , the velocity with which it strikes the thief's car is

54 m/s

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150 m/s

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450 m/s

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250 m/s

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Solution

The correct option is B $150 m/s$
Effective speed of the bullet, $V_{b} =$ muzzle velocity $+$ speed of police jeep
$\Rightarrow V_{b} = 180 m/s + 45 km/h$
$\Rightarrow V_{b} = 180 m/s + 12.5 m/s$
$\Rightarrow V_{b} = 192.5 m/s$
Speed of thief, $V_{t} = 153 km/h = 42.5 m/s$
Velocity of bullet w.r.t. thief's car,
$V_{b, t} = V_{b} - V_{t}$
$V_{b, t} = 192.5 - 42.5 = 150 m/s$

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Q. A police jeep is chasing with, velocity of 45 km/h a thief in another jeep moving with velocity 153 km/h. Police fires a bullet with muzzle velocity of 180 m/s. The velocity it will strike the car of the thief is

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A police van moving on a highway with a speed of 30 km/h fires a bullet at a thief's car speeding away in the same direction with a speed of 192 km/h. If the nuzzle speed of the bullet is 150 m/s, with what speed does the bullet hit the thief's car?

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Relative Velocity in 2D

Standard XII Physics

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A police jeep travelling at a speed of 45 km/h is chasing a thief's car moving at a speed of 153 km/h. If police fire a bullet with a muzzle velocity of 180 m/s, the velocity with which it strikes the thief's car is

The correct option is B 150 m/sEffective speed of the bullet, Vb= muzzle velocity + speed of police jeep ⇒Vb=180 m/s+45 km/h ⇒Vb=180 m/s+12.5 m/s ⇒Vb=192.5 m/s Speed of thief, Vt=153 km/h=42.5 m/s Velocity of bullet w.r.t. thief's car, Vb,t=Vb−Vt Vb,t=192.5−42.5=150 m/s

A police jeep travelling at a speed of $45 km/h$ is chasing a thief's car moving at a speed of $153 km/h$ . If police fire a bullet with a muzzle velocity of $180 m/s$ , the velocity with which it strikes the thief's car is