A polygon has $44$ diagonals. The number of its sides are

9

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10

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11

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12

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Solution

The correct option is B $11$
$T h e n u m b e r o f d i a g o n a l s f o r a n n s i d e d p o l y g o n = \frac{n (n - 3)}{2} ∵ n u m b e r o f d i a g o n a l s = 44 ∴ n (n - 3) = 88 ∴ n = 11$

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Similar questions

A polygon has 44 diagonals, then the number of its sides are

If a polygon has 44 diagonals, then the number of its sides are

44

11

44

\frac{n (n - 3)}{2},

n

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