A polygon has prime number of sides. If number of sides is equal to the sum of the two least consecutive primes. The number of diagonals of the polygon is

4

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5

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7

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Solution

The correct option is C $5$
Two least consecutive prime numbers are $2$ and $3$
$∴$ Number of sides of polygon $= 2 + 3 = 5$
$∴$ Numbers of diagonals $= 5$

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Similar questions

A polygon has prime number of sides. If the number of sides is equal to the sum of the two least consecutive primes.The number of diagonals of the polygon is

Question 13
A polygon has prime number of sides. Its number of sides is equal to the sum of the two least consecutive primes. The number of diagonals of the polygon is
a) 4
b) 5
c) 7
d) 10

Question 13
A polygon has prime number of sides. Its number of sides is equal to the sum of the two least consecutive primes. The number of diagonals of the polygon is
a) 4
b) 5
c) 7
d) 10

Q. If a polygon has

6

5 diagonals, then the number of sides of the polygon is

Q. Assertion :If a polygon has

35

diagonals then the number of the sides of the polygon is

15

. Reason: The number of diagonals of polygon with

n

sides is

\frac{n (n - 3)}{2}

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A polygon has prime number of sides. If number of sides is equal to the sum of the two least consecutive primes. The number of diagonals of the polygon is

The correct option is C 5Two least consecutive prime numbers are 2 and 3∴ Number of sides of polygon =2+3=5∴ Numbers of diagonals =5

The correct option is C $5$
Two least consecutive prime numbers are $2$ and $3$
$∴$ Number of sides of polygon $= 2 + 3 = 5$
$∴$ Numbers of diagonals $= 5$