A polygon having rotational symmetry of order more than 1 cannot have angle of rotation equal to

90^o

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120^o

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125^o

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36^o

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Solution

The correct option is C
125^o

For a regular polygon, number of rotational symmetry exactly divides 360⁰. Since 360⁰ is not divisible by 125⁰, hence the answer.

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Similar questions

Can we have a rotational symmetry of order more than 1 whose angle of rotation is

(i) 45°?

(ii) 17°?

45^{\circ}

A figure with angle of rotation as $17^{\circ}$ has rotational symmetry of order more than 1.

Identify a quadrilateral with a rotational symmetry of order more than 1 but does not have a line symmetry.

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