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Question

A polynomial f(x)−a4x4+a3x3+a2x2+a1x−a0 with all coefficients positive has

A
no real roots
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B
no negative real root
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C
odd number of real roots
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D
at least one positive and one negative real root
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Solution

The correct option is D at least one positive and one negative real root
f(x)=a4x4+a3x3+a2x2+a1xa0
a0,a1,a2,a3,a4>0
f(x) has one change of sign
So f(x) will have maximum one +ve real root
f(x)=a4x4a3x3+a2x2+a1xa0
f(x) has 3 changes of sign
So, f(x) has at most 3 -ve real root
f(x) has atleast one positive and one negative real root.

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