MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Factor Theorem

A polynomial ...

Question

A polynomial p(x) when divided by x - 2 leaves a remainder 12.

P(x) = x^3+2x^2+x-6.

Find all its zeroes.

Open in App

Solution

This equation is not solvable.

Suggest Corrections

thumbs-up

1

Similar questions

Q. Let p(x) be a polynomial of degree more than 2. When p(x) is divided by x-2, it leaves remainder 1 and when it is divided by x-3, it leaves remainder 3. Find the remainder, when p(x) is divided by (x-2)(x-3).

Q. A polynomial p(x) when divided by

x^{2} - 3 x + 2

leaves remainder 2x-3. Then

p (x)

be a quadratic polynomial with constant term

1

p (x)

, when divided by

x - 1

leaves remainder

2

and when divided by

x + 1

leaves remainder

4

. Then the sum of the roots of

p (x) = 0

p (x)

is a polynomial of degree greater than

2

p (x)

leaves remainder

a

- a

when divided by

x + a

x - a

respectively. If

p (x)

x^{2} - a^{2}

then remainder is

Q. The polynomial

p (x) = a x^{3} + 4 x^{2} + 3 x - 4

q (x) = x^{3} - 4 x + a

leave same remainder when divided by

(x - 3)

a

and hence find the remainder when

p (x)

(x - 2) .

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Factor Theorem

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard X Mathematics

Join BYJU'S Learning Program

CrossIcon