A porter lifts a language of $15 k g$ from the ground and puts it on his head $1.5 m$ above the ground. Calculate the work done by him on the luggage.

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Solution

Given data,
$M = 15 k g$
$g = 9.8 m / s^{2}$
$h = 1.5 m$

work done by porter on luggage = force * displacement

$= m g h$

$= 15 \times 9.8 \times 1.5$

$= 220.5 J$

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A porter lifts a language of 15 kg from the ground and puts it on his head 1.5 m above the ground. Calculate the work done by him on the luggage.

Given data,M=15kgg=9.8m/s2h=1.5mwork done by porter on luggage = force * displacement=mgh=15×9.8×1.5=220.5J

A porter lifts a language of $15 k g$ from the ground and puts it on his head $1.5 m$ above the ground. Calculate the work done by him on the luggage.

Given data,
$M = 15 k g$
$g = 9.8 m / s^{2}$
$h = 1.5 m$

work done by porter on luggage = force * displacement

$= m g h$

$= 15 \times 9.8 \times 1.5$

$= 220.5 J$