A portion of a conductive wire is bent in the form of a semicircle of radius r as shown below in figure. At the centre of semicircle, the magnetic induction will be:
A
zero
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B
inifinite
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C
μ04π⋅πi2rtesla
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D
μ04π⋅πirtesla
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Solution
The correct option is Dμ04π⋅πirtesla The straight part will not contribute magnetic field at the centre of the semicircle because every element of the straight part will be 0o or 180o with the line joining the centre and the element.
Due to circular portion, the field is 12μ0i2r=μ0i4r