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Question

A portion of a tube shown in the figure. Fluid is flowing from cross-section area A1 to A2. The two cross-sections are at a distance l from each other. The velocity of the fluid at section A2 is gl2. If the pressure at A1 & A2 is the same, then the angle made by the tube with the horizontal will be.
295987_9cc60a0dfa074fb496c297110ad51392.png

A
37
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B
sin134
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C
53
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D
None of these
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Solution

The correct option is B sin134
equation of continuity
if P1=P2
the ρ1A1v1=ρ2Av2[ρ1=ρ2=ρ]
A1v1=A2v2
Av1=2Av2
v1=2v2
& given v2=9l2
So v1=2gl
by energy balance
KE=mglsinθ
12m(v21v22)=mglsinθ
(2glgl2)=2glsinθ
32=2sinθ
θ=sin134

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