A position dependent force $F = 7 - 2 x + 3 x^{2}$ acts on a small body of mass 2 kg and displaces it from x = 0 to x = 5m. The work done in joules is

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A position dependent force F = 3x2−2x+7 acts on a body of mass 7 kg and displace it from x = 10 m to x = 5 m. The work done on the body is x′ joule. If both F and x′ are measured in SI units, the value of x′ is :

The correct option is A -835Given that F=3x2−2x+7Mass of body = 7 kgWork done by force, W=∫510F⋅dx=∫510(3x2−2x+7)dx=[x3−x2+7x]510=−835 J

A position dependent force F = $3 x^{2} - 2 x + 7$ acts on a body of mass 7 kg and displace it from $x$ = 10 m to $x$ = 5 m. The work done on the body is $x^{'}$ joule. If both $F$ and $x^{'}$ are measured in SI units, the value of $x^{'}$ is :

The correct option is A -835
Given that
$F = 3 x^{2} - 2 x + 7$

Mass of body = $7 k g$

Work done by force, $W = \int_{10}^{5} F \cdot d x = \int_{10}^{5} (3 x^{2} - 2 x + 7) d x = [x^{3} - x^{2} + 7 x]_{10}^{5} = - 835 J$