A position vector is $\to P = 3^k + 2^i - 4^j$ , the magnitude of component of the vector lying perpendicular to the $x - y$ and $x - z$ plane respectively are

3, - 4

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3, 4

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2, - 4

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2, 4

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Solution

The correct option is B $3, 4$
Given the position vector as $\to P = 3^k + 2^i - 4^j$
So, the component of the vector lying in perpendicular to $x - y$ plane is ${\to P}_{z} = 3^k$ , so, $| {\to P}_{z} | = 3$
Similarly, the component of the vector lying in perpendicular to $x - z$ plane is ${\to P}_{y} = - 4^j$ , so, $| {\to P}_{y} | = 4$

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Similar questions

Q. A position vector is

\to P = 3^k + 2^i - 4^j

, the magnitude of component of the vector lying perpendicular to the

x - y

and

x - z

plane respectively are

What are the initial position vector ${\to r}_{i}$ and final position vector ${\to r}_{f}$ , both in unit-vector notation? What is the x component of displacement $Δ \to r$ ?

(i)	Position vector ${\to r}_{i}$	(x)	$5^i - 3^j - 1^k$
(ii)	Postion vector ${\to r}_{f}$	(y)	$- 2^i - 4^j + 1^k$
(iii)	x-component of displacement $Δ \to r$	(z)	$7^i + 1^j - 2^k$

What are the initial position vector ${\to r}_{i}$ and final position vector ${\to r}_{f}$ , both in unit-vector notation? What is the x component of displacement $Δ \to r$ ?

(i) Position vector ${\to r}_{i}$ (x) $5^i - 3^j - 1^k$
(ii) Postion vector ${\to r}_{f}$ (y) $- 2^i - 4^j + 1^k$
(iii)x-component of displacement $Δ \to r$ (z) $7^i + 1^j - 2^k$