A position vector is →P=3^k+2^i−4^j, the magnitude of component of the vector lying perpendicular to the x−y and x−z plane respectively are
A
3,−4
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B
3,4
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C
2,−4
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D
2,4
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Solution
The correct option is B3,4 Given the position vector as →P=3^k+2^i−4^j
So, the component of the vector lying in perpendicular to x−y plane is →Pz=3^k, so, |→Pz|=3
Similarly, the component of the vector lying in perpendicular to x−z plane is →Py=−4^j, so, |→Py|=4