A positive charge q exerts a force of magnitude - 0.2 N on another charge, which has a magnitude twice as the other charge. Find the magnitude of each charge if the distance separating them is equal to 50 cm. (Ans = 1.66 × 10-6 C)

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Solution

F = k (q) ( - 2q) / r² , r = 0.5 m , F = - 0.20 N ,

- 0.2 = - 2 q² k / 0.5²

q² = 0.2 × 0.5² / (2 k)

q = √ [ (0.2 × 0.5² / (2 × 9 × 10⁹) ] = 1.66 × 10^-6 C

q = 1.66 × 10^-6 C

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A positive charge q exerts a force of magnitude - 0.2 N on another charge, which has a magnitude twice as the other charge. Find the magnitude of each charge if the distance separating them is equal to 50 cm. (Ans = 1.66 × 10-6 C)

F = k (q) ( - 2q) / r2 , r = 0.5 m , F = - 0.20 N , - 0.2 = - 2 q2 k / 0.52 q2 = 0.2 × 0.52 / (2 k) q = √ [ (0.2 × 0.52 / (2 × 9 × 109) ] = 1.66 × 10-6 C q = 1.66 × 10-6 C

F = k (q) ( - 2q) / r² , r = 0.5 m , F = - 0.20 N ,

- 0.2 = - 2 q² k / 0.5²

q² = 0.2 × 0.5² / (2 k)

q = √ [ (0.2 × 0.5² / (2 × 9 × 10⁹) ] = 1.66 × 10^-6 C

q = 1.66 × 10^-6 C