Question

A positive charged particle enters in a magnetic field such that the component of its velocity along the field is 3 m/s and perpendicular to the field is 2 m/s. If the Time period of the particle to turn by $2\pi$ radians is 2 s, what will be its pitch?

• A. 5 m
• B. 6 m
• C. 4 m
• D. 8 m

Answer 1

The correct option is B 6 m

The component of velocity along the field will make the charge move in a helical motion. Right?
So the distance covered by the particle along the field in one time period=2x3=6 m.