A positive charged particle enters in a magnetic field such that the component of its velocity along the field is 3 m/s and perpendicular to the field is 2 m/s. If the Time period of the particle to turn by 2π radians is 2 s, what will be its pitch?
A
5 m
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B
6 m
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C
4 m
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D
8 m
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Solution
The correct option is B 6 m The component of velocity along the field will make the charge move in a helical motion. Right? So the distance covered by the particle along the field in one time period=2x3=6 m.