wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A positive charged particle of charge q and mass m is projected with speed v perpendicular to a uniform magnetic field B as shown in the figure. Neglecting gravity, calculate the xcoordinate of the point on the screen at which the charged particle will hit.

Take, d=R32; where R=mvqB


A
3R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2R
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2.5R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.5R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2R


From the figure,

tanθ=PSPB=PSd

PS=dtanθ

Also,

sinθ=dR

Given, d=R32 and R=mvBq

sinθ=R32R

θ=60

Now, AB=RRcos60=R2

Further, xcoordinate where it strikes is

x=AB+PS

x=R2+dtan60

x=R2+R32×3=2R

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, option (B) is the correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Charge Motion in a Magnetic Field
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon