No, we cannot.
By Euclid's lemma, b = aq+r, 0≤r<3
So, this must be in the form 3q, 3q + 1 or 3q + 2.
Now, (3q)2=9q2=3m
and (3q+1)2=9q2+6q+1
= 3(3q2+2q)+1=3m+1 [where, m=3q2+2q]
Also, (3q+2)2=9q2+12q+4
= 9q2+12q+3+1
3(3q2+4q+1)+1
= 3m + 1 [here, m=3q2+4q+1]
Hence, square of a positive integer is of the form 3q + 1 is always in the form 3m + 1 for some integer m.