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Question

A Positively charged oil droplet remains in the electric field between two horizontal plates separated by a distance 1 cm. If the charge on the drop is 3.2×1019C and the mass of the drople is 1014 the potential difference the plates is

A
3125 V
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B
2532 V
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C
4978 V
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D
6162 V
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Solution

The correct option is A 3125 V
FE=mgq[V103]=1014×103.2×109.(V102)=1013V=10133.2×1017=100003.2=3125VHence,optionAiscorrectanswer.

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