The correct option is
C 250m/sGiven :
E=0.1N/C B=4.0×10−4TThe electric force on the particle is canceled by the magnetic force so that the particle moves in the region with velocity v without any deviation in its trajectory i.e Fe=Fm
∴ qE=qvB ⟹v=EB
v=0.14×10−4=250 m/s