A positron is emitted from 11Na24. The ratio of the atomic mass and atomic number of the resulting nuclide is
(IIT-JEE, 2007)
23/10
11Na23⟶10Na23+−1e0
A nuclide A (with mass number m and atomic number n) disintegrates emitting an alpha and one beta particle. The resulting nuclide B has mass number and atomic number respectively equal to