A possible value of x, for which the ninth term in the expansion of {3log3√25x−1+7+3(−18)log3(5x−1+1)}10 in the increasing powers of 3(−18)log3(5x−1+1) is equal to 180, is
A
−1
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B
0
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C
1
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D
2
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Solution
The correct option is C1 Given expression reduces to [(52(x−1)+7)12+(5x−1+1)−18]10
Ninth term is 10C8(52(x−1)+7)(5x−1+1)−1=180
Let 5x−1=t (t2+7)(t+1)−1=4 ⇒t2+7=4t+4⇒t2−4t+3=0⇒(t−3)(t−1)=0 ⇒5x−1=1 or 3 x=1 or x=1+log53