A potential barrier of 0.5V exists across a p-n junction. If the width of depletion layer is 10−6m, then intensity of electric field in this region will be
A
1×106V/m
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B
5×105V/m
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C
4×104V/m
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D
2×106V/m
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Solution
The correct option is A5×105V/m Intensity of electric field is, E=Vd=0.510−6=5×105V/m