A potential barrier of 0.5 V exists across a pn-junction having depletion region (0.8 μm wide). An electron approaches from n-side with K.E 0.6 eV. Find E in depletion region and K.E of electron when it enters p-side.
A
E=6.25×105V/m,K.E=1.1eV
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B
E=6.25×105V/m,K.E=0.1eV
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C
E=6.25×106V/m,K.E=0.1eV
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D
E=6.25×106V/m,K.E=1.1eV
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Solution
The correct option is BE=6.25×105V/m,K.E=0.1eV E=ΔVd=0.50.8×10−6=58×106=6.25×105V/m