A potential difference of 2 V exists across a potentiometer wire of 2 m length- When the potential difference across a 2- resistance of a second circuit is measured by the potentiometer wire- it amounts to 5 mm balancing length- The current in the second circuit is

The correct option is C 2.5 mAP.G = Δ Vl = 22 = 1 vm ⇒ #160; Δ Vl = 1 ⇒ #160; Δ V #160; across #160; #160; resistance #160; = 1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Multiplication & Division of Errors

A potential d...

Question

A potential difference of $2 V$ exists across a potentiometer wire of $2 m$ length. When the potential difference across a $2 Ω$ resistance of a second circuit is measured by the potentiometer wire, it amounts to $5 m m$ balancing length. The current in the second circuit is

2.5 mA

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3 mA

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.5 mA

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 mA

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 2.5 mA
P.G $= \frac{Δ V}{l} = \frac{2}{2} = 1 \frac{v}{m}$
$\Rightarrow \frac{Δ V}{l} = 1$
$\Rightarrow Δ V a c r o s s r e s i s t a n c e = \frac{1 \times 5}{1000} = 0.005 V$
$\Rightarrow I = \frac{Δ V}{r} = 0.0025 = 2.5 m A$

Suggest Corrections

Similar questions

Q. A potentiometer having the potential gradient of

2 m V / c m

is used to measure the difference of potential across a resistance of

10 Ω

. If a length of

50 c m

of the potentiometer wire is required to get the null points the current passing through

10 Ω

resistor is (in

m A

)

Q. An ideal battery of emf

2 V

and a series resistance

R

are connected in the primary circuit of a potentiometer of length

1

m and resistance

Ω

. The value of

R

to give a potential difference of

5

mV across the 10cm of potentiometer wire is:

Q. A standard cell of emf

E_{0} = 1.11 V

is balanced against

72 cm

length of a potentiometer. The same potentiometer is used to measure the potential difference across the standard resistance

R = 120 Ω

. When the ammeter shows a current of

7.8 mA

, a balanced length of

60 cm

is obtained on the potentiometer. Estimate the percentage error in the measurement of ammeter:

Q. An ideal battery of

4 V

and resistance

R

are connected in series in the primary circuit of a potentiometer of length

1 m

and resistance

5 Ω

. The value of

R

, to given a potential difference of

5 m V

across

10 c m

of potentiometer wire is:

Q. In an experiment for calibration of voltmeter, a standard cell of emf 1.5V is balanced at 375cm length of potentiometer wire. The potential difference across a resistance in the circuit is balanced at 1.25 m. If a voltmeter is connected across the same resistance, it reads 0.6V. The error in the voltmeter is

Join BYJU'S Learning Program

A potential difference of 2V exists across a potentiometer wire of 2m length. When the potential difference across a 2Ω resistance of a second circuit is measured by the potentiometer wire, it amounts to 5mm balancing length. The current in the second circuit is

The correct option is C 2.5 mAP.G =ΔVl=22=1vm⇒ΔVl=1⇒ΔVacross resistance=1×51000=0.005V⇒I=ΔVr=0.0025=2.5mA

A potential difference of $2 V$ exists across a potentiometer wire of $2 m$ length. When the potential difference across a $2 Ω$ resistance of a second circuit is measured by the potentiometer wire, it amounts to $5 m m$ balancing length. The current in the second circuit is

The correct option is C 2.5 mA
P.G $= \frac{Δ V}{l} = \frac{2}{2} = 1 \frac{v}{m}$
$\Rightarrow \frac{Δ V}{l} = 1$
$\Rightarrow Δ V a c r o s s r e s i s t a n c e = \frac{1 \times 5}{1000} = 0.005 V$
$\Rightarrow I = \frac{Δ V}{r} = 0.0025 = 2.5 m A$