A potential difference of 20 kV is plied across and X - ray tube. The minimum wavelength of X-rays generated is ___Å. (IIT JEE 1996)

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Solution

The maximum kinetic energy of an electron here is 20000eV. Hence the minimum wavelength will be $λ = \frac{h c}{E} = \frac{1240 e V - n m}{20000 e V} = 0.062 n m = 0.62 A .$

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