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Standard XII

Physics

Conductivity and Resistivity

A potential e...

Question

A potential energy function is shown in graph. A particle moving in this potential field in positive x-direction possess 3 J of kinetic energy at x = 1 m. Where will it reverse its direction?

1 m

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2 m

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5 m

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6 m

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Solution

The correct option is D 6 m
Total energy at $x = 1$ is T.E = 3 J + 3 J = 6 J

when its reverse direction K.E = 0

So T.E = P.E

i.e. P.E = 6 J which is at $x = 6 m$

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A potential energy function is shown in graph. A particle moving in this potential field in positive x-direction possess 3 J of kinetic energy at x = 1 m. Where will it reverse its direction?

The correct option is D 6 mTotal energy at x=1 is T.E = 3 J + 3 J = 6 J when its reverse direction K.E = 0 So T.E = P.E i.e. P.E = 6 J which is at x=6m

The correct option is D 6 m
Total energy at $x = 1$ is T.E = 3 J + 3 J = 6 J

when its reverse direction K.E = 0

So T.E = P.E

i.e. P.E = 6 J which is at $x = 6 m$