wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A potentiometer consists of a wire of length 4m and resistance 10Ω. It is connected to a cell of e.m.f. 3V. The potential gradient of wire is

A
0.75 V/m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2 V/m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
6 V/m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
10 V/m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0.75 V/m

Step 1: Potentiometer Figure

Using KVL in above simple circuit of 1 loop, we get current I=VR=310=0.3 A

AB is potentiometer wire
From figure we can say that potential difference across AB will be equal to e.m.f of cell.

VAB=E=3 V, Also VAB=IR

VAB=0.3×10=3 V

Step 2: Potential gradient calculation

Potential gradient K=VABL

=34=0.75 V/m

Hence, Option A is correct.

2110541_203120_ans_6baf565b22db48ecb5a285308402c9c2.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electrical Instruments
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon