A potentiometer was used to compare EMF’s of two cells. One of them had a slider position of 6m and the other had a slider position of 9m. If the first cell has an emf of 2V, what is the emf of the second?

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Solution

The correct option is A 3V
We know the potential drop across the potentiometer is proportional to the length where slider is in zero position. And if we connect two different batteries, the two lengths we get will be proportional to their EMFs
$\frac{E_{1}}{E_{2}} = \frac{L_{1}}{L_{2}} \frac{2}{E_{2}} = \frac{6}{9} E_{2} = 3 V$

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A potentiometer was used to compare EMF’s of two cells. One of them had a slider position of 6m and the other had a slider position of 9m. If the first cell has an emf of 2V, what is the emf of the second?

The correct option is A 3VWe know the potential drop across the potentiometer is proportional to the length where slider is in zero position. And if we connect two different batteries, the two lengths we get will be proportional to their EMFs E1E2=L1L22E2=69E2=3V