MyQuestionIcon

3

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Potentiometer

A potentiomet...

Question

A potentiometer wire is 100 cm long and a constant p.d. is maintained across it. Two cells A and B are connected in series first and then in opposition. The balance points were obtained at 50 cm and 30 cm. Find the ratio of the e.m.f.s of the cells.

A

1:2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

3:2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

4:1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

3:5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 4:1
$\frac{E_{1}}{E_{2}} = \frac{l_{1} + l_{2}}{l_{1} - l_{2}} = \frac{50 + 30}{50 - 30} = \frac{80}{20} = \frac{4}{1} E_{1} : E_{2} = 4 : 1$

Suggest Corrections

thumbs-up

0

Similar questions

Q. A potentiometer wire is 100 cm long and a constant p.d. is maintained across it. Two cells A and B are connected in series first and then in opposition. The balance points were obtained at 50 cm and 30 cm. Find the ratio of the e.m.f.s of the cells.

Q. A potentiometer wire is

100

cm long and a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obtained at

50

10

cm from the positive end of the wire in the two cases. The ratio of emf's is:

Q. Potentiometer wire is

100 cm

long and a constant potential difference is maintaned across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obtained at

50 cm

10 cm

from the positive end of the wire in the two cases. The ratio of emf's is:

Q. A potentiometer wire is 100 cm long and a constant potential difference is maintained across it. Two cells are connected in series ﬁrst to support one another and then in opposite direction. The balance points are obtained at 50cm and 10cm from the positive end of the wire in the two cases. The ratio of emf's is:

Q. Potentiometer wire is

100 cm

long and a constant potential difference is maintaned across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obtained at

50 cm

10 cm

from the positive end of the wire in the two cases. The ratio of emf's is:

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Electrical Instruments

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard XIII Physics

Join BYJU'S Learning Program

CrossIcon