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Question

A potentiometer wire of length 200cm has a resistance of 20Ω. It is connected in series with a resistance of 10Ω and an accumulator of emf 6V having negligible internal resistance. A source of 2.4V is balanced against a length L of the potentiometer wire. The value of L is?

A
100cm
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B
120cm
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C
110cm
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D
140cm
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Solution

The correct option is B 120cm
I=VR=610+20=630=15A
Voltage across wire =615×10=4V
Voltage per unit length =4200=0.02v/s
Length for balancing =2.42×100cm=120cm
Answer B

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