Given,
Primary voltage, V1=2200
No. of turns in Primary winding, N1=3000
Secondary voltage, V2=220
It is asked to find out the number of turns in the secondary winding.
We have
N1N2=V1V2
Substituting the values in the above equation we get,
3000N2=2200220
By solving the equation we get,
3000N2=101
10N2=3000
N2=300010=300
Hence the number of turns in secondary winding is 300