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Standard XII

Physics

Inductors in Circuits

A power trans...

Question

A power transmission line feeds input power at $2300 V$ to a step-down transformer with its primary windings having $4000$ turns. What should be the number of turns in the secondary coil in order to get output power at $230 V$ ?

100

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300

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400

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600

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Solution

The correct option is C $400$
Using the transformer equation, we have,

$\frac{E_{S}}{E_{P}} = \frac{N_{S}}{N_{P}}$

$\Rightarrow N_{S} = \frac{E_{S}}{E_{P}} \times N_{P} = \frac{230}{2300} \times 4000$

$\Rightarrow N_{S} = 400$

Hence, option $(C)$ is the correct answer.

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A power transmission line feeds input power at 2300 V to a step-down transformer with its primary windings having 4000 turns. What should be the number of turns in the secondary coil in order to get output power at 230 V?

The correct option is C 400Using the transformer equation, we have, ESEP=NSNP ⇒NS=ESEP×NP=2302300×4000 ⇒NS=400 Hence, option (C) is the correct answer.

A power transmission line feeds input power at $2300 V$ to a step-down transformer with its primary windings having $4000$ turns. What should be the number of turns in the secondary coil in order to get output power at $230 V$ ?

The correct option is C $400$
Using the transformer equation, we have,

$\frac{E_{S}}{E_{P}} = \frac{N_{S}}{N_{P}}$

$\Rightarrow N_{S} = \frac{E_{S}}{E_{P}} \times N_{P} = \frac{230}{2300} \times 4000$

$\Rightarrow N_{S} = 400$

Hence, option $(C)$ is the correct answer.