A pressure equivalent to 1 mm of mercury is called

1 torr

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1 bar

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1 pascal

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1 atm

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Solution

The correct option is D 1 torr
The pressure at the bottom of $760 m m$ of mercury is equal to atmospheric pressure.
Also, $1 a t m = 760 t o r r$
Hence, $1 t o r r$ pressure and $1 m m$ of mercury are equivalent.

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Similar questions

The pressure exerted by exactly 1 mm of mercury column at $0^{\circ}$ and at standard gravity is termed as

The atmospheric pressure is usually measured in the unit of :
(a) newtons per square metre (b) Pascal
(c) cm of mercury (d) mm of mercury

1 {cm}^{3}

0^{\circ}

10^{- 5} mm

760 mm

1 atm

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